This project contains model files from the paper describing a representative computational models of lung tissue as a solid material, a randomized hexagonal lattice, and a lattice including a filled in solid representative of a tumor (PLOS computational Biology, 2022)
Owner: mherron
Rebecca G. Zitnay, Michael R. Herron, Keith R. Carney, Scott Potter, Lyska L. Emerson, Jeffrey A. Weiss, & Michelle C. Mendoza (2022). Mechanics of lung cancer: A finite element model shows strain amplification during early tumorigenesis. PLOS Computational Biology, 18(10), e1010153. DOI: 10.1371/journal.pcbi.1010153
lung
cancer
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1-NormalLung.feb
This model is the randomized lung lattice of 10 μm shell elements that undergoes 50% elongation in X and Y with plane strain boundary conditions in Z in steps of 5%. This model uses a Young’s Modulus value of = 3.50716-08, equivalent to 35 kPa, and a Poisson’s ratio of 0.25.
2-2kpaTumor.feb
Lung Lattice (1-NormalLung.feb) with a centrally located tumor comprised of solid elements. Tumor is surrounded by a basement membrane of triangular elements. Young’s modulus of tumor = 2-09, equivalent to 2 kPa with a tumor Poisson’s ratio of 0.49.
3-20kPaTumor.feb
Lung Lattice (1-NormalLung.feb) with a centrally located tumor comprised of solid elements. Tumor is surrounded by a basement membrane of triangular elements. Young’s modulus of tumor = 2-09, equivalent to 2 kPa with a tumor Poisson’s ratio of 0.49.
S1-1-SolidLung-Birzle.feb
Solid rectangular prism that models bulk lung based off the strain energy function proposed by Birzle et. al, 2019. This is the model used for parameter optimization of our lung lattice model of the normal lung composed of shell elements.
S1-2-LatticeLung-neohookean.feb
This is the normal lung lattice model that matches the dimensions of S1-1-SolidLung-Birzle used for parameter optimization.
S2-Indentation.feb
Simulated AFM model of a rigid body indentation into a rectangular prism with the material properties used for the 1-NormalLung.feb. This model uses a Young’s Modulus value of = 3.50716-08, equivalent to 35 kPa, and a Poisson’s ratio of 0.25.